字典翻译 问答 小学 数学 【ab(c²-d²)-(a²-d²)cdx的2n次方+x的n次方-1/9y的4m次方+1/4(1+y)²-2x²(1+y²)+x4(1-y)²x²-y²+2x+6y-8-14x²y²+x4+y4】
问题标题:
【ab(c²-d²)-(a²-d²)cdx的2n次方+x的n次方-1/9y的4m次方+1/4(1+y)²-2x²(1+y²)+x4(1-y)²x²-y²+2x+6y-8-14x²y²+x4+y4】
问题描述:

ab(c²-d²)-(a²-d²)cd

x的2n次方+x的n次方-1/9y的4m次方+1/4

(1+y)²-2x²(1+y²)+x4(1-y)²

x²-y²+2x+6y-8

-14x²y²+x4+y4

梁利生回答:
  ab(c²-d²)-(a²-b²)cd   =abc²-abd²-a²cd+b²cd   =(abc²-a²2cd)+(b²cd-abd²)   =ac(bc-ad)+bd(bc-ad)   =(ac+bd)(bc-ad);   x^(2n)+x^n-1/9y^(4m)+1/4   =[x^(2n)+x^n+1/4]-1/9y^(4m)   =(x^n+1/2)²-(1/3y^2m)²   =(x^n+1/2+1/3y^2m)(x^n+1/2-1/3y^2m)   (1+y)²-2x²(1+y)²+x^4(1+y)²   =(1+y)²[1-2x²+x^4]   =(1+y)²(1-x²)²   =(1+y)²(1+x)²(1-x)²   x²-y²+2x+6y-8   =(x²+2x+1)-(y²-6y+9)   =(x+1)²-(y-3)²   =(x+y-2)(x-y+4)   -14x²y²+x^4+y^4   =x^4+y^4+2x²y²-16x²y²   =(x²+y²)²-16x²y²   =(x²+y²+4xy)(x²+y²-4xy)   =[(x+2y)^2-3y^2][(x-2y)^2-3y^2]   =(x+2y+√3y)(x+2y-√3y)(x-2y+√3y)(x-2y-√3y)
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