问题标题：
设z=e^xysin(x+y).计算dz.要直接能抄的
问题描述：
设z=e^xysin(x+y).计算dz.要直接能抄的
胡白燕回答：
是否求函数z=e^xy*cos(x+y)的全微分dzz=e^xy*cos(x+y)Z'x=ye^xycos(x+y)-e^xysin(x+y)Z'y=xe^xycos(x+y)-e^xysin(x+y)故dZ=[ye^xycos(x+y)-e^xysin(x+y)]dx+[xe^xycos(x+y)-e^xysin(x+y)]dy
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