问题标题：
【动摩擦系数0.4,先从50m坡上滑下,再上30m坡,再滑下,求回到平面后的滑行距离,质量为210kg.Abobsledrunleadsdownahillassketchedinthefigureabove.BetweenpointsAandD,frictionisnegligible.BetweenpointsDandEatt】
问题描述：
动摩擦系数0.4,先从50m坡上滑下,再上30m坡,再滑下,求回到平面后的滑行距离,质量为210kg.
Abobsledrunleadsdownahillassketchedinthefigureabove.BetweenpointsAandD,frictionisnegligible.BetweenpointsDandEattheendoftherun,thecoefficientofkineticfrictionissub>k=0.4.Themassofthebobsledwithdriversis210kganditstartsfromrestatpointA.
FindthedistancexbeyondpointDatwhichthebobsledwillcometoahalt
李鹤回答：
如果图是按我理解那样的话,
mgh=mgu*s
s=h/u=125m
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