问题标题：
设a1,a2,a3为3维列向量,行列式|a1a2a3|=d,则|3a1+a22a1a3|=
问题描述：
设a1,a2,a3为3维列向量,行列式|a1a2a3|=d,则|3a1+a22a1a3|=
陈冬冬回答：
|3a1+a22a1a3|
=|a22a1a3+|3a12a1a3|
=|a22a1a3|+0
=-|2a1a2a3|
=-2^3|a1a2a3|
=-8|a1a2a3|
=-8d
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