问题标题：
llllllllllllllllllllllllllllllllllllllllllllllllll(1811:40:56)已知函数f（X）=ax+b,若f(0)=1,且f(x+1)=f(x+1)=f(x)+3,求f(x).
问题描述：
llllllllllllllllllllllllllllllllllllllllllllllllll(1811:40:56)
已知函数f（X）=ax+b,若f(0)=1,且f(x+1)=f(x+1)=f(x)+3,求f(x).
李明利回答：
将f（0）带进去得到b=1,则f（x+1）=a（x+1）+1,f（x）+3=ax+4
又f(x+1)=f(x)+3,即a（x+1）+1=ax+4化简得到a=3
所以f(x）=3x+1
点击显示
数学推荐
热门数学推荐