问题标题:
已知y-2x=0,求代数式[(x+y)(x-xy+y)]÷[(x+xy+y)(x-y)]的值?
问题描述:
已知y-2x=0,求代数式[(x+y)(x-xy+y)]÷[(x+xy+y)(x-y)]的值?
唐昊回答:
Y=2X原式=[(x+4X)(x-2x+4X)]÷[(x+2x+4X)(x-4X)]=[(5X)(3X)]÷[(7X)(-3X)]=-5/7
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