问题标题：
几道有关分式加减乘除的题目!计算2/X-1-(1-3X)/2-2X结果计算a-b+2b²/a+b=化简(1-1/a-2)÷3-a/2a-4已知a+b=3,ab=1,则a/b+b/a=化简（x-1/y）÷（y-1/x)=若x等于它的倒数,则x²-4x+4/x+3÷x-2/x²+6x+9
问题描述：
几道有关分式加减乘除的题目!
计算2/X-1-(1-3X)/2-2X结果
计算a-b+2b²/a+b=
化简(1-1/a-2)÷3-a/2a-4
已知a+b=3,ab=1,则a/b+b/a=
化简（x-1/y）÷（y-1/x)=
若x等于它的倒数,则x²-4x+4/x+3÷x-2/x²+6x+9
何增有回答：
2/(X-1)-(1-3X)/(2-2X)
=2/(X-1)+(1-3X)/{2(X-1)}
=(2*2+1-3X)/{2(X-1)}
=(5-3X)/{2(X-1)}
a-b+2b^2/(a+b)
={(a-b)(a+b)+2b^2}/(a+b)
={a^2-b^2+2b^2)/(a+b)
=(a^2+b^2)/(a+b)
{(1-1/(a-2)}÷(3-a)/(2a-4)
=(a-2-1)/(a-2)*2(a-2)/{-(a-3)}
=-(a-3)/(a-2)*2(a-2)/(a-3)
=-2
a+b=3,ab=1
a/b+b/a
=(a^2+b^2)/(ab)
={(a+b)^2-2ab}/(ab)
={3^2-2*1}/1
=7
（x-1/y）÷（y-1/x)
=(xy-1)/y÷（xy-1)/x
=xy
x=1/x
x^2=1
x=±1
(x²-4x+4)/(x+3)÷(x-2)/(x²+6x+9)
=(x-2)^2/(x+3)*(x+3)^2/(x-2)
=(x+3)(x-2)
=x^2+x-6
=1+x-6
=x-5
=±1-5
=-6,或-4
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