问题标题:
化简根号2(sinx-cosx)
问题描述:
化简根号2(sinx-cosx)
戴新宇回答:
根号2(sinx-cosx)
=2(√2/2sinx-√2/2cosx)
=2(sinxcosπ/4-cosxsinπ/4)
=2sin(x-π/4)
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