问题标题:
Inonemodelofthehydrogenatom,theelectronrevolvesinacircularorbitaroundtheprotonwithaspeedof2.0106m/s.Determinetheradiusoftheelectron'sorbit.
问题描述:
Inonemodelofthehydrogenatom,theelectronrevolvesinacircularorbitaroundtheprotonwithaspeedof2.0106m/s.Determinetheradiusoftheelectron'sorbit.
唐同诰回答:
kQq/r²=mv²/rk=9×10^9N·m²/C²Q=q=1.6×10^-19Cm=9.1×10^-31kgr=kQq/mv²(速度不对吧,那么慢的电子,怎么也该是它的几十万、上百万倍)(先按2×10^6m/s算)=6.3×10^-11m=63pm...
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