问题标题：
f(n)=1/n+1+1/n+2+1/n+3+……+1/3n,则f(k+1)-f(k)=
问题描述：
f(n)=1/n+1+1/n+2+1/n+3+……+1/3n,则f(k+1)-f(k)=
邱继涛回答：
f(k+1)-f(k)=1/(3k+1)+1/(3k+2)+1/(3k+3)-1/(k+1)=1/(3k+1)+1/(3k+2)-2/(3k+3)>0
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