问题标题：
(1-1/2-1/3-...-1/2009)(1/2+1/3+1/4...+1/2010)-(1-1/2-1/3-...-1/2009-1/2010)(1/2+1/3...+1/2009)
问题描述：
(1-1/2-1/3-...-1/2009)(1/2+1/3+1/4...+1/2010)-(1-1/2-1/3-...-1/2009-1/2010)(1/2+1/3...+1/2009)
林仲卯回答：
let
x=1/2+1/3+...+1/2009
(1-1/2-1/3-...-1/2009)(1/2+1/3+1/4...+1/2010)-(1-1/2-1/3-...-1/2009-1/2010)(1/2+1/3...+1/2009)
=(1-x)(x+1/2010)-(1-x-1/2010)x
=[x+1/2010-x^2-x/2010]-[x-x^2-x/2010]
=1/2010
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