问题标题：
一道数学三角函数化简题(asin派/5+bcos派/5)/(acos派/5-bsin派/5)=(tan派/5+b/a)/(1-b/a﹡tan派/5)为什么啊.
问题描述：
一道数学三角函数化简题
(asin派/5+bcos派/5)/(acos派/5-bsin派/5)=(tan派/5+b/a)/(1-b/a﹡tan派/5)为什么啊.
罗茂松回答：
右=(tanπ/5+b/a)/(1-b/a*tanπ/5)右=(sinπ/5/cosπ/5+b/a)/(1-b/a*sinπ/5/cosπ/5)分子、分母同乘a*cosπ/5右=(asinπ/5+bcosπ/5)/(a*cosπ/5-bsinπ/5)左=(asinπ/5+bcosπ/5)/(a*cosπ/5-bsinπ/5)所以：左=...
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