问题标题:
数学(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/2007-1/2008)=?
问题描述:
数学(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/2007-1/2008)=?
姜松回答:
(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/2007-1/2008)=1-1/2+1/2-1/3+1/3-1/4+...+1/2007-1/2008=1+(-1/2+1/2)+(-1/3+1/3)+(-1/4+1/4)...+(-1/2007+1/2007)-1/2008=1-1/2008=2007/2008
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