问题标题：
..自学不易..希望达人指教...4x²·(-xy²)³(1.3·10^5)(3.8·10^3)(4a-b²)·(-2b)2x²(x-½)5ab·(2a-b+0.2)(2a²-2/3a-4/9)·(-9a)(x-6)·(x-3)(x+½)·(x-1/3)(3x+2)(x+2)(4y-1)·(y-5
问题描述：
..自学不易..希望达人指教...
4x²·(-xy²)³(1.3·10^5)(3.8·10^3)
(4a-b²)·(-2b)2x²(x-½)
5ab·(2a-b+0.2)(2a²-2/3a-4/9)·(-9a)
(x-6)·(x-3)(x+½)·(x-1/3)
(3x+2)(x+2)(4y-1)·(y-5)
(x-2)(x²+4)(x-y)(x²+xy+y²)
x²(x-1)-x(x²+x-1)已知x=½
(x-3)(x-3)·6(x²+X-1)
(2x+1)²-(x+3)-(x-1)²+!
求运算步骤和结果...
..只是初二上学期的整式乘法....需要题的运算步骤和结果--
卿杜政回答：
4x²·(-xy²)³=-4x^2*x^3*4x^2*y^6=-4x^5*y^6.（幕的运算）(1.3·10^5)(3.8·10^3)=(1.3*3.8)*10^(5+3)=4.94*10^8.（幕的运算）(4a-b²)·(-2b)=-8ab+2b^32x²(x-½)=2x^...
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