问题标题：
化简根号下(1-2sin10°cos10°)/[cos10°-根号下(1-sin^280°)]
问题描述：
化简根号下(1-2sin10°cos10°)/[cos10°-根号下(1-sin^280°)]
牛悦苓回答：
根号下(1-2sin10°cos10°)/[cos10°-根号下(1-sin^280°)]
=根号下(sin10°-cos10°)^2/[cos10°-根号下(cos^280°)]
=|sin10°-cos10°|/[cos10°-cos80°]cos10°>sin10°cos80°=sin10°
=(cos10°-sin10°)/(cos10°-sin10°)
=1
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