问题标题:
数学题求解······好了,加分·······每一步写清楚(1)(a+b-3)(a-b+3)(2)(m²+n-7)(m²-n-7)(3)(a²+b)(a²-b)(4)(-4m²+5)(4m²+5)(5)(x²-y²)(x²+y²)(6)(9a
问题描述:
数学题求解······好了,加分·······每一步写清楚
(1)(a+b-3)(a-b+3)
(2)(m²+n-7)(m²-n-7)
(3)(a²+b)(a²-b)
(4)(-4m²+5)(4m²+5)
(5)(x²-y²)(x²+y²)
(6)(9a²+7b²)(7b²-9a²)
````````分`````````````割````````````````线```````````````
(7)(2m+3)(2m-3)
(8)x(x+1)+(2-x)(2+x)
(9)(3x-y)(3x+y)+y(x+y)
(10)(a+12b)(a-12b)-(3a-2b)(3a+2b)
乔惊天回答:
1.a²-(b-3)²=a²-b²+6b-92.(m²-7)²-n²3.(a²)²-b²4.25-(4m²)²5.(x²)²-(y²)²6.(7b²)²-(9a²)²7.4m²-98.x&...
徒君回答:
过程详细一点,,,详细的话,给你加分
乔惊天回答:
全部都是直接应用平方差公式的:(a+b)(a-b)=a^2-b^2像第一题有点变化,(a+b-3)(a-b+3)看成[a+(b-3)]*[a-(b-3)],代入公式就得到了a²-(b-3)²剩下的就只是化简了,还有不清楚的吗
徒君回答:
每一步都详细写,我给你加分,15分再加10分,只要过程详细,
乔惊天回答:
贴了个图片,看得见么??
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