问题标题:
【数学三角函数函数f(x)=2sinxcosx+2sin(x+π/4)sin(x+3π/4)+1.怎么把函数f(x)=2sinxcosx+2sin(x+π/4)sin(x+3π/4)+1.拆开,再结合,】
问题描述:
数学三角函数函数f(x)=2sinxcosx+2sin(x+π/4)sin(x+3π/4)+1.
怎么把函数f(x)=2sinxcosx+2sin(x+π/4)sin(x+3π/4)+1.拆开,再结合,
方明回答:
f(x)=2sinxcosx+2sin(x+π/4)sin(x+3π/4)+1=2sinxcosx+2﹙sinxcosπ/4+cosxsinπ/4)﹙sinxcos3π/4+cosxsin3π/4)+1=2sinxcosx+2﹙√2/2sinx+√2/2cosx)﹙√2/2cosx-√2/2sinx)+1=2s...
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