问题标题：
【有关日历计算,要求输入n,输出从2000.1.1开始往后n天的那一天的年月日星期.GiventhenumberofdaysthathaveelapsedsinceJanuary1,2000A.D,yourmissionistofindthedateandthedayoftheweek.InputTheinputconsistsofl】
问题描述：
有关日历计算,
要求输入n,输出从2000.1.1开始往后n天的那一天的年月日星期.
GiventhenumberofdaysthathaveelapsedsinceJanuary1,2000A.D,yourmissionistofindthedateandthedayoftheweek.
Input
Theinputconsistsoflineseachcontainingapositiveinteger,whichisthenumberofdaysthathaveelapsedsinceJanuary1,2000A.D.Thelastlinecontainsaninteger-1,whichshouldnotbeprocessed.Youmayassumethattheresultingdatewon'tbeaftertheyear9999.
Output
Foreachtestcase,outputonelinecontainingthedateandthedayoftheweekintheformatof"YYYY-MM-DDDayOfWeek",where"DayOfWeek"mustbeoneof"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday"and"Saturday".
SampleInput
1730
1740
1750
1751
-1
SampleOutput
2004-09-26Sunday
2004-10-06Wednesday
2004-10-16Saturday
2004-10-17Sunday
要c的
贾方回答：
以下是用C++写的
#include
structInNum
{
intnum;
InNum*next;
};
voidmain()
{
intyear=2000,day=1,mouth=1,dayTemp=0,week0=6,week;
InNum*head,*last,*p;
head=newInNum;
head->next=NULL;
last=head;
p=newInNum;
cin>>p->num;
p->next=NULL;
last->next=p;
last=last->next;
while(p->num>0)
{
p=newInNum;
cin>>p->num;
p->next=NULL;
last->next=p;
last=last->next;
}
p=head->next;
while(p->num>=0)
{
p->num--;
while(p->num>=365)
{
year++;
p->num-=365;
}
dayTemp=p->num;
while(p!=NULL&&p->num>28)
{
if(2==mouth&&0==year%4&&p->num>=29)
{
mouth++;
p->num-=29;
}
elseif(2==mouth&&p->num>=28)
{
mouth++;
p->num-=28;
}
elseif(mouthnum>mouth%2+30)
{
p->num-=(mouth%2+30);
mouth++;
}
elseif(mouth>=9&&p->num>(mouth+1)%2+30)
{
p->num-=((mouth+1)%2+30);
mouth++;
}
else
break;
}
day=p->num;
week=(dayTemp+year-2001+1)%7;
cout
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