问题标题：
【化简：根号下n(n+1)(n+2)(n+3)+1】
问题描述：
化简：根号下n(n+1)(n+2)(n+3)+1
李家霁回答：
根号下n(n+1)(n+2)(n+3)+1
=根号下n(n+3)(n+1)(n+2)+1
=(n^2+3n)(n^2+3n+2)+1
设（n^2+3n）为k,
原式=根号下k（k+2）+1
=根号下(k^2+2k+1)
=根号下(k+1)^2
=k+1=n^2+3n+1
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